Medium
Convert the following into basic $SI$ units:
$(i)$ $28.7 \, pm$
$(ii)$ $15.15 \, pm$
$(iii)$ $25365 \, mg$
$(i)$ $28.7 \, pm$
$(ii)$ $15.15 \, pm$
$(iii)$ $25365 \, mg$
The $SI$ unit of length is $\text{metre}$ $(m)$ and the $SI$ unit of mass is $\text{kilogram}$ $(kg)$.
The conversions are as follows:
$(i)$ $28.7 \, pm = 28.7 \times 10^{-12} \, m = 2.87 \times 10^{-11} \, m$
$(ii)$ $15.15 \, pm = 15.15 \times 10^{-12} \, m = 1.515 \times 10^{-11} \, m$
$(iii)$ $25365 \, mg = 25365 \times 10^{-6} \, kg = 2.5365 \times 10^{-2} \, kg$
The conversions are as follows:
$(i)$ $28.7 \, pm = 28.7 \times 10^{-12} \, m = 2.87 \times 10^{-11} \, m$
$(ii)$ $15.15 \, pm = 15.15 \times 10^{-12} \, m = 1.515 \times 10^{-11} \, m$
$(iii)$ $25365 \, mg = 25365 \times 10^{-6} \, kg = 2.5365 \times 10^{-2} \, kg$
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